23y^2=-27y

Solution for 23y^2=-27y equation:

23y^2=-27y

We move all terms to the left:

23y^2-(-27y)=0

We get rid of parentheses

23y^2+27y=0

a = 23; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·23·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*23}=\frac{-54}{46}
=-1+4/23
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*23}=\frac{0}{46}
=0
$